Hi Helene
It is a good questions.
You are right that the 5000N is a pretty big force, but this fully
intended. The explanation is that we want to create a unilateral
constraint this can be done these muscles, they can push the buckle
forward. The strength has to be high because we do not want these
muscles to be the “bottleneck” in the muscles recruitment. Using
this high strength they are not close to the activity envelope, and
they work as “almost infinitley strong” unilateral constraint.
In reality it would be better to have real unilateral contraints
without using these muscles, but this is how we can do this
currently.
Best regards
Søren AnyBody Support
— In anyscript@yahoogroups.com, helene randal petersen
<helenerandal@…> wrote:
>
> Hi Søren…
>
> Thanks a lot for all your help…now I have one last question!
> In the BuckleSupport.any 5 artificial pushing muscles are applied,
and they are said to work with a strength each of 5000 (N?). But I
can not find out which unit these 5000 are in?? Because 5000 N for
each seems as a tremendously big force!
>
> Best regards
>
> Helene
>
>
> To: anyscript@…: support@…: Thu, 21 Jun 2007 07:07:06
+0000Subject: [AnyScript] Re: How is the force in the abdomen
measured??
>
>
>
>
> Hi HelenaThis variable F was used for scaling purposes, when
developing the model, but as you can see it is set to one so it do
not have any influence, it will always stay as one. So it is really
something which should just be removed…I hope it made it more
clear, the abdominal model is one of the most complex model parts we
have, so i can undestand if you are confused ;-)Best regardsSøren—
In anyscript@yahoogroups.com, helene randal petersen <helenerandal@>
wrote:>> Hi Søren> > Thank you for your reply. I looked up what the
AnyKinMeasureLinComp means, and I see that it needs both the
Coefficient matrix and the Constant as an input.> But I don’t
understand what F is:> > AnyVar F=1; > Coef={>
{FDisc1Coef,FDisc2Coef,FDisc3Coef,FDisc4Coef,FDisc5Coef,Fdvdh}
> };> Why is it included, is it something that has to be there for
the AnyKinMeasureLinComp, and when it is defined as F=1 is it then a
initial condition as the case with R = 0.12 and H0=0.28, or is it
always taking into account as F=1?> > If it’s a force, then it has N
as unit , and the Disc1Coef and so on has the unit m^2, and then I
end up with kgm^3/s^2!!> > Okay as you see I’m confused!> > Helene>
> > To: anyscript@: support@: Sun, 17 Jun 2007 10:52:03
+0000Subject: [AnyScript] Re: How is the force in the abdomen
measured??> > > > Hi HeleneIn the buckle.any file there is a linear
combination measure named as AnyKinMeasureLinComb AbdominalVol=
{This is basically the abdominal volume the equation you are missing
i think is the coefficient matrix named Coef=
{{FDisc1Coef,FDisc2Coef,FDisc3Coef,FDisc4Coef,FDisc5Coef,F*dvdh}
}; This where all the components are added togetherinto a linear
equation. If needed please see the manual for details about the
AnyKinMeasureLinComb which is used for this.The abdominal muscle is
applied to the muscle volume measure, this means that the force from
this muscle will be “splitted” into a number of individual forces.
These forces are dependent on the coefficent vector and the measures
being used.So in words the there will be a force between pelvis and
thorax and forces which will push the buckle forward, and forces
which will push on L1 to L5.Please ask again if you have further
questions.Best regardsSøren, AnyBody Support— In
anyscript@yahoogroups.com, “helene.randal” <helenerandal@> wrote:>>
Hi…> > I’m working with the intra-abdominal pressure, or better
described, > I’m looking at the file that models the abdominal
pressure, which is > the Buckle.any. At the same time I’m looking at
the slides from > www.anybody.aau.dk. But I can’t understand how the
model uses the > volume to calculate the pressure.> 1) If you look
at the slide called Abdominal pressure implementation, > then there
is an equation that defines the total volume. I’m able to > find out
where the different components of this equation comes from, > and
how they are calculated, but I don’t see an equation that > connects
it all into the total volume. 2)And another question if says > in
the file Buckle.any that when a force is applied to this volume, >
then it becomes an abdominal pressure, but how should that be >
understood? They define some pressure nodes in the “center” of
pelvis > and thorax where to the force from the abdominal pressure
is applied, > but still I don’t get it!!> > I hope this is
understandable…sometimes it’s a bit difficult to > explain what
it is that you exactly don’t understand!!> > Helene> > > >
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