Hi,
I could understand the reactions in AnyStdJoint here:
http://wiki.anyscript.org/images/3/33/AnyStdJointReactions.any
We can define a AnyStdJoint very easy:
AnyStdJoint FixJoint1 =
{
AnyRefFrame& ref1 = ..Ref1;
AnyRefFrame& ref2 = ..Ref2;
};
And we can define a AnyStdJoint in a different way:
AnyKinEqSimpleDriver FixJoint2 =
{
AnyKinLinear Lin =
{
Ref = 0;
AnyRefFrame& ref1 = ...Ref1;
AnyRefFrame& ref2 = ...Ref2;
};
AnyKinRotational Rot=
{
//Ref = 0;
[b]Type = RotAxesAngles;[/b]
Axis1 = x; Axis2 = y; Axis3 = z;
AnyRefFrame& ref1 = ...Ref1;
AnyRefFrame& ref2 = ...Ref2;
};
MeasureOrganizer = {0,1,2,3,4,5};
DriverPos = {0, 0, 0, 0, 0, 0};
DriverVel = {0, 0, 0, 0, 0, 0};
};
For the reactions in the AnyStdJoint, we can understand that the reaction forces and torques are like this:
Fx,Fy,Fz,Mz,My,Mx = Fout[0],Fout[1],Fout[2],Fout[3],Fout[4],Fout[5]
Then in the case of FixJoint2 defined as AnyKinEqSimpleDriver using AnyKinLinear and AnyKinRotational class above code, I guess like this:
Fx,Fy,Fz,Mx,My,Mz = Fout[0],Fout[1],Fout[2],Fout[3],Fout[4],Fout[5]
Because in the AnyKinRotational object I set its type as ‘RotAxesAngles’ and set their axes as ‘Axis1 = x’, ‘Axis2 = y’ and ‘Axis3 = z’.
I would just like to know whether my guess is right or wrong.
Best regards and thanks in advance,
Moonki